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Lesson 4: Basic Differentiation Rules

Estimated time: 30-40 minutes

Learning Objectives

By the end of this lesson, you will be able to:

The Constant Rule

Constant Rule: If f(x) = c (a constant), then f'(x) = 0.

The graph of a constant is a horizontal line, so its slope is zero everywhere.

The Power Rule

Power Rule: If f(x) = xn for any real number n, then f'(x) = nxn−1.

This works for positive integers, negative integers, and even fractions (rational exponents).

Example 1: Power Rule Applications

(a) d/dx [x5] = 5x4

(b) d/dx [x−3] = −3x−4 = −3/x4

(c) d/dx [√x] = d/dx [x1/2] = (1/2)x−1/2 = 1/(2√x)

(d) d/dx [x] = 1x0 = 1

Constant Multiple Rule

Constant Multiple Rule: d/dx [c · f(x)] = c · f'(x).

You can "factor out" constants when differentiating.

Example 2: Constant Multiples

(a) d/dx [7x4] = 7 · 4x3 = 28x3

(b) d/dx [−3x2] = −3 · 2x = −6x

(c) d/dx [(4/3)x6] = (4/3)(6x5) = 8x5

Sum and Difference Rules

Sum Rule: d/dx [f(x) + g(x)] = f'(x) + g'(x)

Difference Rule: d/dx [f(x) − g(x)] = f'(x) − g'(x)

Differentiate term by term.

Example 3: Differentiating a Polynomial

Find d/dx [3x4 − 2x3 + 7x − 5].

Solution: Differentiate each term:

= 3(4x3) − 2(3x2) + 7(1) − 0 = 12x3 − 6x2 + 7

Example 4: Rewriting Before Differentiating

Find f'(x) for f(x) = (3x² + 2)/x.

Step 1: Rewrite: f(x) = 3x + 2x−1

Step 2: f'(x) = 3 + 2(−1)x−2 = 3 − 2/x²

Derivatives of Exponential and Logarithmic Functions

Exponential: d/dx [ex] = ex (the only function that is its own derivative!)

Natural Logarithm: d/dx [ln x] = 1/x for x > 0

Example 5: Mixed Functions

Find d/dx [5ex − 3 ln x + x4].

= 5ex − 3/x + 4x3

Finding Tangent Lines with Rules

Example 6: Tangent Line

Find the tangent line to f(x) = x3 − 4x + 2 at x = 1.

Step 1: f(1) = 1 − 4 + 2 = −1. Point: (1, −1).

Step 2: f'(x) = 3x² − 4. f'(1) = 3 − 4 = −1.

Step 3: y − (−1) = −1(x − 1), so y = −x.

Higher-Order Derivatives

The derivative of the derivative is called the second derivative: f''(x) or d²y/dx². You can continue: f'''(x), f(4)(x), etc.

Example 7: Higher Derivatives

f(x) = x5 − 3x3 + x

f'(x) = 5x4 − 9x² + 1

f''(x) = 20x3 − 18x

f'''(x) = 60x² − 18

Key Takeaways

Check Your Understanding

1. Find f'(x) for f(x) = 4x3 − 2x + 9.

12x² − 2

2. Find g'(x) for g(x) = 5/x² + 3√x.

Rewrite: 5x−2 + 3x1/2. g'(x) = −10x−3 + (3/2)x−1/2 = −10/x³ + 3/(2√x).

3. Find the second derivative of h(x) = ex + x4.

h'(x) = ex + 4x3. h''(x) = ex + 12x².

4. Find the tangent line to y = 2ex at x = 0.

y(0) = 2. y' = 2ex, y'(0) = 2. Tangent: y − 2 = 2(x − 0), or y = 2x + 2.

Module 2 Complete!

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