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Lesson 3: Curve Sketching

Estimated time: 40-50 minutes

Learning Objectives

Curve Sketching Checklist

Systematic Curve Sketching Procedure

  1. Domain: Where is f defined?
  2. Intercepts: x-intercepts (set f = 0) and y-intercept (evaluate f(0)).
  3. Symmetry: Is f even, odd, or periodic?
  4. Asymptotes: Vertical (denominator = 0), horizontal (limits at ±∞).
  5. First derivative: Increasing/decreasing intervals and local extrema.
  6. Second derivative: Concavity and inflection points.
  7. Plot key points and connect the dots using all information above.

Worked Example

Example 1: Sketch f(x) = x³ − 3x²

Domain: All real numbers.

Intercepts: f(0) = 0. f(x) = x²(x − 3) = 0 at x = 0, 3.

Symmetry: Neither even nor odd.

Asymptotes: None (polynomial).

f'(x) = 3x² − 6x = 3x(x − 2). Critical points: x = 0, 2.

f' > 0 on (−∞, 0), f' < 0 on (0, 2), f' > 0 on (2, ∞).

Local max at (0, 0), local min at (2, −4).

f''(x) = 6x − 6. f'' = 0 at x = 1. Concave down on (−∞, 1), concave up on (1, ∞). Inflection point at (1, −2).

Sketch: Rises to (0, 0), falls to (2, −4), then rises through (3, 0) and beyond. Changes concavity at (1, −2).

Example 2: Sketch f(x) = x/(x² + 1)

Domain: All reals. Intercepts: (0, 0). Symmetry: f(−x) = −f(x), so f is odd.

Asymptotes: No vertical. Horizontal: limx→±∞ x/(x²+1) = 0, so y = 0.

f'(x) = (1 − x²)/(x² + 1)². f' = 0 at x = ±1.

f' > 0 on (−1, 1): increasing. f' < 0 outside: decreasing.

Local min at (−1, −1/2), local max at (1, 1/2).

f''(x) = 2x(x² − 3)/(x² + 1)³. Inflection at x = 0, ±√3.

Key Takeaways

Check Your Understanding

1. What are the key features to plot for f(x) = x4 − 4x²?

Answer: Even function. y-int: (0,0). x-int: x = 0, ±2. f'(x) = 4x³ − 8x = 4x(x−√2)(x+√2). Local max at (0,0), local min at (±√2, −4). f'' = 12x² − 8, inflection at x = ±√(2/3).

2. Name the first step you should always take when sketching a curve.

Answer: Determine the domain of the function.

3. If a function has a horizontal asymptote y = 3, what does that tell you about the graph?

Answer: As x → ∞ or x → −∞ (or both), the graph approaches the line y = 3.

4. For f(x) = x³ − 3x², identify the inflection point.

Answer: f''(x) = 6x − 6 = 0 at x = 1. f(1) = −2. Inflection point: (1, −2).

Ready for More?

Next Lesson

Lesson 4: Optimization Problems.

Start Lesson 4