Learn Without Walls
← Module 8 Home Lesson 2 of 4 Next Lesson →

Lesson 2: Integrals Involving Trig Functions

Estimated time: 40-50 minutes

Learning Objectives

By the end of this lesson, you will be able to:

Key Trig Identities for Integration

Essential Identities

Pythagorean: sin²x + cos²x = 1,   tan²x + 1 = sec²x

Half-angle (power-reduction):

sin²x = (1 − cos 2x)/2,   cos²x = (1 + cos 2x)/2

Double angle: sin 2x = 2 sin x cos x

Strategy for ∫ sinmx cosnx dx

Decision Tree

  • At least one odd power: Strip off one factor of sin x (or cos x), convert the remaining even powers using sin²x = 1 − cos²x (or cos²x = 1 − sin²x), then use u-substitution with u = cos x (or u = sin x).
  • Both even powers: Use power-reduction (half-angle) identities to reduce the powers.

Example 1: Odd Power of Sine

Evaluate ∫ sin³x cos²x dx.

Step 1: sin³x = sin²x · sin x = (1 − cos²x) sin x.

Step 2: Let u = cos x, du = −sin x dx.

∫ (1 − u²) u² (−du) = −∫ (u² − u4) du = −u³/3 + u5/5 + C

= −cos³x/3 + cos5x/5 + C.

Example 2: Even Powers (Both Even)

Evaluate ∫ sin²x dx.

Step 1: Use power-reduction: sin²x = (1 − cos 2x)/2.

∫ (1 − cos 2x)/2 dx = x/2 − sin(2x)/4 + C = x/2 − sin(2x)/4 + C.

Example 3: cos²x sin²x

Evaluate ∫ cos²x sin²x dx.

Step 1: Use identity: cos x sin x = sin(2x)/2, so cos²x sin²x = sin²(2x)/4.

Step 2: Apply power-reduction: sin²(2x) = (1 − cos 4x)/2.

∫ (1 − cos 4x)/8 dx = x/8 − sin(4x)/32 + C.

Integrals Involving Tangent and Secant

Example 4: ∫ tan²x dx

Use the identity tan²x = sec²x − 1:

∫ (sec²x − 1) dx = tan x − x + C.

Example 5: ∫ sec³x dx (preview)

This integral requires integration by parts (covered in Lesson 3). The result is:

∫ sec³x dx = (1/2)[sec x tan x + ln|sec x + tan x|] + C.

This formula is worth memorizing as it appears frequently.

Products of Different Angles

For integrals like ∫ sin(mx) cos(nx) dx, use the product-to-sum formulas:

Product-to-Sum Formulas

sin A cos B = (1/2)[sin(A + B) + sin(A − B)]

sin A sin B = (1/2)[cos(A − B) − cos(A + B)]

cos A cos B = (1/2)[cos(A − B) + cos(A + B)]

Example 6: Product-to-Sum

Evaluate ∫ sin(3x) cos(5x) dx.

Step 1: = (1/2) ∫ [sin(8x) + sin(−2x)] dx = (1/2) ∫ [sin(8x) − sin(2x)] dx.

= (1/2)[−cos(8x)/8 + cos(2x)/2] + C = −cos(8x)/16 + cos(2x)/4 + C.

Introduction to Trig Substitution

Some integrals involve expressions like √(a² − x²), √(a² + x²), or √(x² − a²). These can be simplified with a trigonometric substitution:

Trig Substitution Guidelines

ExpressionSubstitutionIdentity Used
√(a² − x²)x = a sin θ1 − sin²θ = cos²θ
√(a² + x²)x = a tan θ1 + tan²θ = sec²θ
√(x² − a²)x = a sec θsec²θ − 1 = tan²θ

Trig Substitution Example

Example 7: Trig Substitution

Evaluate ∫ 1/√(4 − x²) dx.

Step 1: a = 2. Let x = 2 sin θ, dx = 2 cos θ dθ.

Step 2: √(4 − 4 sin²θ) = 2 cos θ.

Step 3: ∫ (2 cos θ)/(2 cos θ) dθ = ∫ dθ = θ + C = arcsin(x/2) + C.

Key Takeaways

Check Your Understanding

1. Evaluate ∫ cos³x dx.

Answer: cos³x = (1 − sin²x) cos x. u = sin x: ∫ (1 − u²) du = u − u³/3 + C = sin x − sin³x/3 + C.

2. Evaluate ∫ cos²x dx.

Answer: = ∫ (1 + cos 2x)/2 dx = x/2 + sin(2x)/4 + C.

3. Evaluate ∫0π/2 sin5x dx.

Answer: sin5x = (1 − cos²x)² sin x. u = cos x: −∫10 (1 − u²)² du = ∫01 (1 − 2u² + u4) du = 1 − 2/3 + 1/5 = 8/15.

Ready for More?

Next Lesson

Lesson 3 covers integration by parts.

Start Lesson 3