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Lesson 3: Derivatives of Trig Functions

Estimated time: 30-40 minutes

Learning Objectives

By the end of this lesson, you will be able to:

Derivatives of Sine and Cosine

Using the limit definition of the derivative along with the special limits limh→0 (sin h)/h = 1 and limh→0 (cos h − 1)/h = 0, we can prove:

The Two Fundamental Trig Derivatives

d/dx [sin x] = cos x

d/dx [cos x] = −sin x

Notice the minus sign on cosine. A helpful mnemonic: derivatives of functions that start with "co-" (cosine, cotangent, cosecant) all pick up a negative sign.

Example 1: Basic Trig Derivatives

Find d/dx [3 sin x − 2 cos x].

Solution: 3 cos x − 2(−sin x) = 3 cos x + 2 sin x

Derivatives of the Other Four Trig Functions

Using the Quotient Rule on the definitions tan x = sin x / cos x, etc., we derive:

All Six Trig Derivatives

FunctionDerivative
sin xcos x
cos x−sin x
tan xsec² x
cot x−csc² x
sec xsec x tan x
csc x−csc x cot x

Example 2: Deriving d/dx [sec x]

Write sec x = 1/cos x and apply the Quotient Rule (or think of it as (cos x)−1 and use the Chain Rule):

d/dx [1/cos x] = −(−sin x)/cos² x = sin x / cos² x = (1/cos x)(sin x/cos x) = sec x tan x

Combining with the Chain Rule

Example 3: Chain Rule with Trig

Find d/dx [tan(5x)].

Outer: tan u. Inner: u = 5x.

d/dx [tan(5x)] = sec²(5x) · 5 = 5 sec²(5x)

Example 4: Product Rule + Trig

Find d/dx [x² cos x].

Product Rule: 2x cos x + x²(−sin x) = 2x cos x − x² sin x

Example 5: Nested Trig Composition

Find d/dx [sec²(3x)].

Rewrite: [sec(3x)]². Outer: u². Inner: sec(3x).

General Power Rule: 2 sec(3x) · d/dx[sec(3x)]

Chain Rule for sec(3x): sec(3x) tan(3x) · 3

Combine: 2 sec(3x) · 3 sec(3x) tan(3x) = 6 sec²(3x) tan(3x)

Key Takeaways

Check Your Understanding

1. Find d/dx [sin x cos x].

Answer: Product Rule: cos x · cos x + sin x · (−sin x) = cos² x − sin² x = cos 2x.

2. Find d/dx [csc(4x)].

Answer: Chain Rule: −csc(4x) cot(4x) · 4 = −4 csc(4x) cot(4x).

3. Find d/dx [tan x / x].

Answer: Quotient Rule: [sec² x · x − tan x · 1] / x² = (x sec² x − tan x) / x².

4. Find d/dx [cos³(2x)].

Answer: Outer: u³, middle: cos v, inner: 2x. Apply chain: 3 cos²(2x) · (−sin(2x)) · 2 = −6 cos²(2x) sin(2x).

Ready for More?

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Lesson 4 covers implicit differentiation for curves defined by equations like x² + y² = 25.

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Module Progress

You have completed Lesson 3!

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