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Lesson 1: Linear Functions

Estimated time: 30-40 minutes

Learning Objectives

By the end of this lesson, you will be able to:

What is a Linear Function?

A linear function is one of the most fundamental concepts in algebra. As the name suggests, when you graph a linear function, you get a perfectly straight line.

Linear Function: A function whose graph is a straight line. It has a constant rate of change and can be written in the form f(x) = mx + b, where m and b are constants.

Linear functions appear everywhere in real life: converting temperatures, calculating costs, determining distance traveled at constant speed, and much more. Understanding linear functions is essential for success in algebra and beyond.

Key Characteristic

The defining feature of a linear function is that it has a constant rate of change. For every unit increase in x, y changes by the same amount. This constant rate of change is called the slope.

Understanding Slope

The slope of a line measures its steepness and direction. Think of it as "how much the line rises (or falls) for every step to the right."

Slope (m): The ratio of vertical change (rise) to horizontal change (run) between any two points on a line.

m = (y₂ - y₁)/(x₂ - x₁) = rise/run

Types of Slope

Positive Slope

m > 0

Line rises from left to right

Example: y = 2x + 1 (slope = 2)

As x increases, y increases

Negative Slope

m < 0

Line falls from left to right

Example: y = -3x + 5 (slope = -3)

As x increases, y decreases

Zero Slope

m = 0

Horizontal line (flat)

Example: y = 4 (slope = 0)

y stays constant as x changes

Undefined Slope

m is undefined

Vertical line

Example: x = 3

Division by zero (run = 0)

Example 1: Calculating Slope

Find the slope of the line passing through points (2, 3) and (5, 9).

Solution:

Step 1: Identify the coordinates

(x₁, y₁) = (2, 3) and (x₂, y₂) = (5, 9)

Step 2: Apply the slope formula

m = (y₂ - y₁)/(x₂ - x₁)

m = (9 - 3)/(5 - 2)

Step 3: Simplify

m = 6/3

m = 2

Answer: The slope is 2. This means for every 1 unit increase in x, y increases by 2 units. The line rises from left to right.

Example 2: Negative Slope

Find the slope of the line passing through points (-1, 4) and (3, -2).

Solution:

m = (y₂ - y₁)/(x₂ - x₁)

m = (-2 - 4)/(3 - (-1))

m = (-6)/(4)

m = -3/2 or -1.5

Answer: The slope is -3/2. The negative slope means the line falls from left to right. For every 2 units to the right, the line drops 3 units.

Example 3: Zero Slope

Find the slope of the line passing through points (1, 5) and (7, 5).

Solution:

m = (y₂ - y₁)/(x₂ - x₁)

m = (5 - 5)/(7 - 1)

m = 0/6

m = 0

Answer: The slope is 0. This is a horizontal line where y always equals 5, regardless of x.

Intercepts

Intercepts are the points where a line crosses the axes. They provide important information about a linear function.

Y-Intercept

Definition: The point where the line crosses the y-axis

x-coordinate is always 0

Written as: (0, b)

To find: Set x = 0 and solve for y

X-Intercept

Definition: The point where the line crosses the x-axis

y-coordinate is always 0

Written as: (a, 0)

To find: Set y = 0 and solve for x

Example 4: Finding Intercepts

Find both intercepts of the line 2x + 3y = 12.

Finding the y-intercept (set x = 0):

2(0) + 3y = 12

3y = 12

y = 4

Y-intercept: (0, 4)

Finding the x-intercept (set y = 0):

2x + 3(0) = 12

2x = 12

x = 6

X-intercept: (6, 0)

Answer: Y-intercept is (0, 4) and x-intercept is (6, 0).

Slope-Intercept Form

The slope-intercept form is the most common and user-friendly way to write linear equations. It immediately shows you the slope and y-intercept.

Slope-Intercept Form

y = mx + b

where:

m = slope (rate of change)

b = y-intercept (where line crosses y-axis)

Example 5: Identifying Slope and Y-Intercept

For the equation y = 4x - 7, identify the slope and y-intercept.

Solution:

This equation is already in slope-intercept form: y = mx + b

Comparing y = 4x - 7 to y = mx + b:

m = 4 (the coefficient of x)

b = -7 (the constant term)

Answer:

Slope = 4 (line rises; for every 1 unit right, go up 4 units)

Y-intercept = -7 (line crosses y-axis at point (0, -7))

Example 6: Writing Equation in Slope-Intercept Form

Write an equation for the line with slope -2 and y-intercept 5.

Solution:

We know: m = -2 and b = 5

Substitute into y = mx + b:

y = -2x + 5

Answer: y = -2x + 5

Example 7: Equation from Two Points

Write the equation of the line passing through points (1, 3) and (4, 12).

Solution:

Step 1: Find the slope

m = (12 - 3)/(4 - 1) = 9/3 = 3

Step 2: Use one point to find b

Using point (1, 3): 3 = 3(1) + b

3 = 3 + b

b = 0

Step 3: Write the equation

y = 3x + 0

y = 3x

Answer: y = 3x

Point-Slope Form

The point-slope form is especially useful when you know the slope and one point on the line (but don't know the y-intercept yet).

Point-Slope Form

y - y₁ = m(x - x₁)

where:

m = slope

(x₁, y₁) = a specific point on the line

Example 8: Using Point-Slope Form

Write the equation of a line with slope 5 passing through point (2, -3).

Solution:

We know: m = 5 and (x₁, y₁) = (2, -3)

Substitute into y - y₁ = m(x - x₁):

y - (-3) = 5(x - 2)

y + 3 = 5(x - 2)

Point-slope form: y + 3 = 5(x - 2)

If we want slope-intercept form, distribute and solve for y:

y + 3 = 5x - 10

y = 5x - 13

Slope-intercept form: y = 5x - 13

Example 9: Point-Slope with Two Points

Write the equation of the line through points (-1, 4) and (3, -2).

Solution:

Step 1: Find the slope

m = (-2 - 4)/(3 - (-1)) = -6/4 = -3/2

Step 2: Choose either point (let's use (-1, 4))

y - 4 = -3/2(x - (-1))

y - 4 = -3/2(x + 1)

Point-slope form: y - 4 = -3/2(x + 1)

Converting to slope-intercept form:

y - 4 = -3/2·x - 3/2

y = -3/2·x - 3/2 + 4

y = -3/2·x + 5/2

Slope-intercept form: y = -3/2·x + 5/2

Standard Form

The standard form is another way to write linear equations. It's useful for quickly finding both intercepts and is preferred in some applications.

Standard Form

Ax + By = C

where:

A, B, C are integers (whole numbers)

A should be positive (if possible)

A, B, C have no common factors other than 1

Example 10: Converting to Standard Form

Convert y = 3x - 7 to standard form.

Solution:

Step 1: Move the x-term to the left side

y = 3x - 7

-3x + y = -7

Step 2: Multiply by -1 to make A positive

3x - y = 7

Answer: 3x - y = 7

Here A = 3, B = -1, C = 7

Example 11: Standard Form to Slope-Intercept

Convert 4x + 2y = 10 to slope-intercept form.

Solution:

Solve for y:

4x + 2y = 10

2y = -4x + 10

y = -2x + 5

Answer: y = -2x + 5

Now we can see: slope = -2, y-intercept = 5

Example 12: Using Standard Form to Find Intercepts

Find both intercepts of 5x + 2y = 20.

Finding x-intercept (set y = 0):

5x + 2(0) = 20

5x = 20

x = 4

X-intercept: (4, 0)

Finding y-intercept (set x = 0):

5(0) + 2y = 20

2y = 20

y = 10

Y-intercept: (0, 10)

Converting Between Forms

Summary: Three Forms of Linear Equations

1. Slope-Intercept Form: y = mx + b

Best for: Graphing, seeing slope and y-intercept at a glance

2. Point-Slope Form: y - y₁ = m(x - x₁)

Best for: When you know slope and a point

3. Standard Form: Ax + By = C

Best for: Finding intercepts quickly, integer coefficients

Example 13: Complete Conversion

Write the line through (2, 5) with slope -3 in all three forms.

Point-Slope Form:

y - 5 = -3(x - 2)

Slope-Intercept Form:

y - 5 = -3x + 6

y = -3x + 11

Standard Form:

3x + y = 11

Check Your Understanding

Try these questions to see if you've grasped the key concepts:

1. Find the slope of the line passing through points (3, 7) and (6, 16).

Answer:
m = (y₂ - y₁)/(x₂ - x₁)
m = (16 - 7)/(6 - 3)
m = 9/3
m = 3
The slope is 3, meaning the line rises 3 units for every 1 unit to the right.

2. What are the slope and y-intercept of the line y = -5x + 8?

Answer: This is in slope-intercept form y = mx + b.
Slope (m) = -5 (the line falls; for every 1 unit right, go down 5 units)
Y-intercept (b) = 8 (the line crosses the y-axis at (0, 8))

3. Find both intercepts of the line 3x - 4y = 24.

X-intercept (set y = 0):
3x - 4(0) = 24
3x = 24
x = 8
X-intercept: (8, 0)

Y-intercept (set x = 0):
3(0) - 4y = 24
-4y = 24
y = -6
Y-intercept: (0, -6)

4. Write the equation of a line with slope 4 and y-intercept -3.

Answer: Using slope-intercept form y = mx + b:
m = 4 and b = -3
y = 4x - 3

5. Write the equation of a line passing through point (1, -2) with slope 6 in point-slope form. Then convert to slope-intercept form.

Point-slope form:
y - y₁ = m(x - x₁)
y - (-2) = 6(x - 1)
y + 2 = 6(x - 1)

Converting to slope-intercept form:
y + 2 = 6x - 6
y = 6x - 8
y = 6x - 8

6. Convert the equation y = 2x + 5 to standard form.

Answer:
y = 2x + 5
-2x + y = 5 (move x-term to left)
Multiply by -1 to make A positive:
2x - y = -5

Key Takeaways

Ready for More?

Next Lesson

In Lesson 2, you'll learn how to apply linear functions to real-world modeling problems. You'll interpret slope and intercepts in context and solve practical problems involving rates, costs, and more!

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Module Progress

You've completed Lesson 1 of Module 2!