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Post-Assessment

Module 5: Systems of Equations & Inequalities

About This Assessment

This post-assessment measures your learning gains after completing Module 5. Comparing your pre- and post-assessment results helps us understand how much you learned!

Time: 5-10 minutes | Questions: 5 | Purpose: Measure learning gains

Question 1

Solve the system using substitution:
y = 3x - 2
y = -2x + 8

A. x = 1, y = 1
B. x = 2, y = 4
C. x = 3, y = 2
D. x = 4, y = 10

Question 2

Solve the system using elimination:
3x + 2y = 16
x - 2y = 0

A. x = 2, y = 2
B. x = 3, y = 3
C. x = 4, y = 2
D. x = 5, y = 1

Question 3

What type of system is this?
x + 2y = 5
2x + 4y = 8

A. Consistent independent (one solution)
B. Consistent dependent (infinitely many solutions)
C. Inconsistent (no solution)
D. Cannot be determined

Question 4

Which region should be shaded for the inequality y < -x + 3?

A. Above the line y = -x + 3
B. Below the line y = -x + 3
C. To the left of the line y = -x + 3
D. To the right of the line y = -x + 3

Question 5

Which point is a solution to this system of inequalities?
y > 2x - 1
y < -x + 4

A. (0, 1)
B. (2, 1)
C. (3, 5)
D. (-1, 0)

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Post-Assessment

About This Assessment

Solve the system using substitution: y = 3x - 2 y = -2x + 8

Solve the system using elimination: 3x + 2y = 16 x - 2y = 0

What type of system is this? x + 2y = 5 2x + 4y = 8

Which region should be shaded for the inequality y < -x + 3?

Which point is a solution to this system of inequalities? y > 2x - 1 y < -x + 4

Ready to Submit?

Module 5 Complete!

Solve the system using substitution:
y = 3x - 2
y = -2x + 8

Solve the system using elimination:
3x + 2y = 16
x - 2y = 0

What type of system is this?
x + 2y = 5
2x + 4y = 8

Which point is a solution to this system of inequalities?
y > 2x - 1
y < -x + 4