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Module 8 Quick Reference

Introduction to Matrices - One-Page Cheat Sheet

Matrix Operations

Addition/Subtraction

A + B = [aij + bij]
A - B = [aij - bij]

Must have same dimensions

Scalar Multiplication

kA = [k · aij]

Multiply each element by k

Matrix Multiplication

If A is m×n and B is n×p, then AB is m×p
(AB)ij = Row i of A · Column j of B
Important: AB is defined only when columns of A = rows of B
Matrix multiplication is NOT commutative: AB ≠ BA

Determinants

2×2 Determinant

det([a b; c d]) = ad - bc

Example: det([3 5; 2 4]) = (3)(4) - (5)(2) = 2

3×3 Determinant

Use cofactor expansion
or row reduction

Expand along row/column with most zeros

Key Properties

  • det(I) = 1
  • det(AB) = det(A) · det(B)
  • det(kA) = kn · det(A) for n×n matrix
  • Swapping rows changes sign
  • Upper triangular: det = product of diagonal

Inverse Matrices

A matrix is invertible if and only if det(A) ≠ 0
If invertible: AA-1 = A-1A = I

2×2 Inverse Formula

For A = [a b; c d], if det(A) ≠ 0:

A-1 = (1/det(A)) · [d -b; -c a]

Steps: 1) Find det(A), 2) Swap diagonal (a↔d), 3) Negate off-diagonal (-b, -c), 4) Multiply by 1/det(A)

Gauss-Jordan Method

[A | I] → [I | A-1]

Use row operations to transform left side to I; right side becomes A-1

Inverse Properties

  • (A-1)-1 = A
  • (AB)-1 = B-1A-1 (reverse order)
  • det(A-1) = 1/det(A)

Solving Matrix Equations

Matrix Equation AX = B

If A is invertible: X = A-1B

Steps

  • 1. Check det(A) ≠ 0
  • 2. Find A-1
  • 3. Calculate X = A-1B
  • 4. Verify: AX = B

System of Equations

Write as AX = B where:

  • A = coefficient matrix
  • X = variable matrix
  • B = constant matrix

Cramer's Rule

Use determinants to solve systems. Works when det(A) ≠ 0

Formula

For AX = B:
x = det(Ax)/det(A)
y = det(Ay)/det(A)
z = det(Az)/det(A)

Where: Ax is matrix A with x-column replaced by constants B, etc.

When to Use

  • Best for: Finding one variable in small systems
  • Requires: Square matrix with det(A) ≠ 0
  • Alternative: Inverse matrix method for all variables

Quick Formula Summary

Operation Formula Requirement
Addition A+B [aij + bij] Same dimensions
Scalar kA [k · aij] None
Multiplication AB Row·Column cols(A) = rows(B)
Det 2×2 ad - bc Square matrix
Inverse 2×2 (1/det)[d -b; -c a] det(A) ≠ 0
Solve AX=B X = A-1B A invertible
Cramer's Rule x = det(Ax)/det(A) det(A) ≠ 0

Common Mistakes to Avoid

  • Order matters: AB ≠ BA (multiplication not commutative)
  • Dimensions: Always check before multiplying
  • Determinant signs: Watch alternating +/- in cofactor expansion
  • Inverse formula: It's [d -b; -c a], not [d b; c a]
  • Scalar determinants: det(kA) = kndet(A), not k·det(A)
  • Check invertibility: Always verify det(A) ≠ 0 before finding inverse

Quick Tips

For Determinants

  • Use 2×2 formula directly
  • For 3×3: expand along row/column with zeros
  • Upper triangular: multiply diagonal

For Inverses

  • Check det(A) ≠ 0 first!
  • 2×2: use formula
  • Larger: Gauss-Jordan
  • Verify: AA-1 = I

Solving Systems

  • One variable → Cramer's
  • All variables → Inverse
  • Always verify solution

Matrix Multiplication

  • Check: cols(A) = rows(B)
  • Result: rows(A) × cols(B)
  • Row dot Column
  • Order matters!

Special Matrices

Type Description Example
Zero Matrix All zeros [0 0; 0 0]
Identity I 1's on diagonal, 0's elsewhere [1 0; 0 1]
Diagonal Non-zero only on diagonal [2 0; 0 3]
Upper Triangular Zeros below diagonal [1 2; 0 3]

Test Day Checklist

Bring: Calculator, pencils, eraser
Know: 2×2 det formula, 2×2 inverse formula, matrix multiplication rule
Check: Dimensions, det ≠ 0, arithmetic, verify answers

Problem-Solving Order

  1. Read problem carefully
  2. Identify what's asked (determinant, inverse, solve system?)
  3. Check requirements (dimensions compatible? det ≠ 0?)
  4. Choose best method
  5. Show all work
  6. Verify answer if time permits