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Lesson 4: Solution Sets -- Unique, Infinite, and None

Estimated time: 35-45 minutes

Learning Objectives

By the end of this lesson, you will be able to:

Three Possibilities for Solution Sets

A system of linear equations has exactly one of three outcomes:

Existence and Uniqueness:

  1. Exactly one solution (consistent, independent) -- the system has a unique answer.
  2. Infinitely many solutions (consistent, dependent) -- free variables parameterize a family of solutions.
  3. No solution (inconsistent) -- the equations contradict each other.

How to Tell from RREF

  • No solution: A row of the form [0 0 ... 0 | b] with b nonzero (contradiction).
  • Unique solution: No contradiction rows, and every column (except the last) is a pivot column.
  • Infinitely many solutions: No contradiction rows, and at least one column (other than the last) is not a pivot column (free variable exists).

Case 1: Unique Solution

Example

RREF:

[ 1   0   0  |   2 ]
[ 0   1   0  |  -1 ]
[ 0   0   1  |   4 ]

Every variable column is a pivot column. There are no free variables.

Solution: x_1 = 2, x_2 = -1, x_3 = 4. The solution set is the single point {(2, -1, 4)}.

Case 2: Infinitely Many Solutions

Example

RREF:

[ 1   0   3   0  |   5 ]
[ 0   1  -2   0  |   1 ]
[ 0   0   0   1  |  -3 ]
[ 0   0   0   0  |   0 ]

Pivot columns: 1, 2, 4. Free variable: x_3 (column 3).

Let x_3 = t where t is any real number. Then:

  • x_1 = 5 - 3t
  • x_2 = 1 + 2t
  • x_3 = t
  • x_4 = -3

Parametric Vector Form

We can write the solution more elegantly by separating the constant part from the part that depends on the free variable:

Parametric Vector Form: Express the solution as a vector sum: a particular solution plus a linear combination of direction vectors scaled by free parameters.

Example: Writing in Parametric Vector Form

From the example above:

x = (5, 1, 0, -3) + t(- 3, 2, 1, 0)

where t can be any real number. Here:

  • (5, 1, 0, -3) is a particular solution (set t = 0)
  • (-3, 2, 1, 0) is the direction vector corresponding to the free variable x_3

Geometrically, the solution set is a line through (5, 1, 0, -3) in the direction (-3, 2, 1, 0) in R^4.

Example: Two Free Variables

RREF:

[ 1   2   0   1  |  3 ]
[ 0   0   1  -1  |  2 ]

Pivot columns: 1, 3. Free variables: x_2 = s, x_4 = t.

From row 1: x_1 = 3 - 2s - t

From row 2: x_3 = 2 + t

x = (3, 0, 2, 0) + s(-2, 1, 0, 0) + t(-1, 0, 1, 1)

The solution set is a plane in R^4, parameterized by two free variables.

Case 3: No Solution

Example

RREF:

[ 1   0   2  |  5 ]
[ 0   1  -1  |  3 ]
[ 0   0   0  |  1 ]

Row 3 says 0 = 1, which is impossible. The system is inconsistent. The solution set is empty.

Geometrically, the planes represented by the equations do not all share a common point.

Homogeneous Systems

Homogeneous System: A system where every constant on the right-hand side is zero: Ax = 0. A homogeneous system always has at least the trivial solution x = 0. It is always consistent.

The interesting question for homogeneous systems is: does it have nontrivial solutions (solutions other than x = 0)?

Key Fact

If a homogeneous system has more unknowns than equations (more columns than rows in the coefficient matrix), it must have a free variable and therefore infinitely many solutions.

Example: Homogeneous System

Solve Ax = 0 where the augmented matrix reduces to:

[ 1   0   2  |  0 ]
[ 0   1  -3  |  0 ]

Free variable: x_3 = t. Solution: x = t(- 2, 3, 1).

The solution set is a line through the origin. For homogeneous systems, the particular solution is always the zero vector, so the solution set is spanned by the direction vectors alone.

Check Your Understanding

1. A system in 4 unknowns reduces to RREF with 3 pivot columns. How many free variables are there? Is the solution unique?

Answer: 4 - 3 = 1 free variable. The solution is NOT unique (assuming the system is consistent); there are infinitely many solutions parameterized by that one free variable.

2. Write the solution in parametric vector form: RREF is [ 1 -1 | 4 ] / [ 0 0 | 0 ].

Answer: Free variable: x_2 = t. From row 1: x_1 = 4 + t. Parametric vector form: x = (4, 0) + t(1, 1).

3. A homogeneous system has 3 equations and 5 unknowns. Can the only solution be the trivial solution?

Answer: No. With 5 unknowns and at most 3 pivots, there are at least 5 - 3 = 2 free variables. The system must have infinitely many (nontrivial) solutions.

4. Classify the system whose RREF is [ 1 0 0 | 3 ] / [ 0 1 0 | -2 ] / [ 0 0 1 | 7 ].

Answer: Consistent with a unique solution (3, -2, 7). Every variable column is a pivot column and there are no contradiction rows.

5. How many direction vectors appear in the parametric vector form if there are 2 free variables?

Answer: Two direction vectors -- one for each free variable. The solution set is a plane (if the system is nonhomogeneous, a translated plane; if homogeneous, a plane through the origin).

Key Takeaways

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