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Lesson 4: Solving Right Triangles and Applications

Estimated time: 30-35 minutes

Learning Objectives

By the end of this lesson, you will be able to:

What Does "Solve a Triangle" Mean?

To solve a right triangle means to find all unknown sides and all unknown angles. Since one angle is always 90°, you need to find the other two angles and any missing sides.

Strategy: Given a right triangle with at least one side and one acute angle (or two sides), use SOH-CAH-TOA and the Pythagorean theorem to find everything else.

Solving When Given an Angle and a Side

Example 1: Finding a Missing Side

In right triangle ABC with C = 90°, angle A = 35° and hypotenuse c = 20. Find side a (opposite A).

Solution:

We know the hypotenuse and want the opposite side. Use sine:

sin 35° = a/20

a = 20 sin 35° = 20(0.5736) ≈ 11.47

Example 2: Finding the Other Side and Angle

Continuing from Example 1, find side b (adjacent to A) and angle B.

Side b: cos 35° = b/20, so b = 20 cos 35° ≈ 20(0.8192) ≈ 16.38

Angle B: B = 90° − 35° = 55°

Solving When Given Two Sides

Example 3: Finding an Angle from Two Sides

A right triangle has legs a = 6 and b = 10. Find angle A (opposite side a).

Solution:

tan A = opposite/adjacent = 6/10 = 0.6

A = tan¹(0.6) ≈ 30.96°

B = 90° − 30.96° ≈ 59.04°

Hypotenuse: c = √(36 + 100) = √136 ≈ 11.66

Angles of Elevation and Depression

Angle of Elevation: The angle measured upward from the horizontal to a line of sight to an object above.

Angle of Depression: The angle measured downward from the horizontal to a line of sight to an object below.

Key insight: the angle of elevation from point A to point B equals the angle of depression from B to A (alternate interior angles).

Example 4: Angle of Elevation

A person standing 50 meters from a building looks up at an angle of elevation of 60° to see the top. How tall is the building? (Assume eye level is at ground level for simplicity.)

Solution:

tan 60° = height / 50

height = 50 tan 60° = 50√3 ≈ 86.6 meters

Example 5: Angle of Depression

From the top of a 200-foot lighthouse, the angle of depression to a boat is 25°. How far is the boat from the base of the lighthouse?

Solution:

The angle of depression from the top equals the angle of elevation from the boat: 25°.

tan 25° = 200 / d, so d = 200 / tan 25° = 200 / 0.4663 ≈ 429 feet

Navigation and Bearing Problems

Example 6: Simple Bearing Problem

A ship sails on a bearing of N 30° E for 100 miles. How far north and how far east has it traveled?

Solution:

The bearing N 30° E means 30° east of due north. Draw a right triangle with the 100-mile path as hypotenuse.

Northward distance = 100 cos 30° = 100(√3/2) ≈ 86.6 miles

Eastward distance = 100 sin 30° = 100(1/2) = 50 miles

Check Your Understanding

1. In a right triangle, angle A = 42° and the side adjacent to A is 15. Find the opposite side.

tan 42° = opp/15, so opp = 15 tan 42° ≈ 15(0.9004) ≈ 13.51.

2. A ladder 20 ft long leans against a wall making a 70° angle with the ground. How high up the wall does it reach?

sin 70° = h/20, h = 20 sin 70° ≈ 20(0.9397) ≈ 18.79 ft.

3. From a point 100 m from a tree, the angle of elevation to the top is 28°. Find the height.

tan 28° = h/100, h = 100 tan 28° ≈ 100(0.5317) ≈ 53.17 m.

Key Takeaways

Module 2 Complete!

Practice Problems

Test your skills with 10 problems on the unit circle and right triangles.

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