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Lesson 3: Reciprocal, Quotient, and Pythagorean Identities

Estimated time: 30-35 minutes

Learning Objectives

By the end of this lesson, you will be able to:

Reciprocal Identities

csc θ = 1/sin θ    sec θ = 1/cos θ    cot θ = 1/tan θ

Equivalently: sin θ = 1/csc θ, cos θ = 1/sec θ, tan θ = 1/cot θ

Quotient Identities

tan θ = sin θ / cos θ     cot θ = cos θ / sin θ

Example 1: Simplifying with Quotient Identity

Simplify: sin θ / cos θ · cos θ

Solution: (sin θ / cos θ) · cos θ = sin θ. The cos θ cancels.

The Three Pythagorean Identities

Identity 1: sin²θ + cos²θ = 1

Identity 2: 1 + tan²θ = sec²θ

Identity 3: 1 + cot²θ = csc²θ

Identity 2 is obtained by dividing Identity 1 by cos²θ:

sin²θ/cos²θ + cos²θ/cos²θ = 1/cos²θ ⇒ tan²θ + 1 = sec²θ

Identity 3 is obtained by dividing Identity 1 by sin²θ:

sin²θ/sin²θ + cos²θ/sin²θ = 1/sin²θ ⇒ 1 + cot²θ = csc²θ

Example 2: Using a Pythagorean Identity

Simplify: sec²θ − tan²θ

Solution: From Identity 2: sec²θ − tan²θ = 1

Example 3: Writing in Terms of Sine and Cosine

Simplify: (1 − cos²θ) / sin θ

Solution: 1 − cos²θ = sin²θ (from Identity 1). So sin²θ / sin θ = sin θ

Example 4: Factoring with Identities

Simplify: sin²θ − 1

Solution: sin²θ − 1 = −(1 − sin²θ) = −cos²θ

Writing One Function in Terms of Another

Example 5: Express tan in Terms of sin

Write tan θ in terms of sin θ only (assume θ is in QI).

Solution: tan θ = sin θ / cos θ. Since cos θ = √(1 − sin²θ) in QI:

tan θ = sin θ / √(1 − sin²θ)

Check Your Understanding

1. Simplify: csc²θ − cot²θ

From Identity 3: 1.

2. Simplify: (sin²θ)(1 + cot²θ)

1 + cot²θ = csc²θ. So sin²θ · csc²θ = sin²θ · (1/sin²θ) = 1.

3. Simplify: tan θ cos θ

(sin θ/cos θ) · cos θ = sin θ.

Key Takeaways

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Even-odd properties and cofunction identities.

Lesson 4

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