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Lesson 3: Finding Probabilities with the Normal Distribution

Master using z-tables to calculate probabilities and percentiles

Area Under the Curve = Probability

One of the most powerful features of the normal distribution is that the area under the curve represents probability. This allows us to calculate the probability that a randomly selected value falls within any range.

Key Concept: Area = Probability

For a continuous distribution like the normal distribution:

  • The total area under the entire curve = 1 (or 100%)
  • The area between two values = probability of getting a value in that range
  • The area to the left of a value = probability of getting a value less than it
  • The area to the right of a value = probability of getting a value greater than it
Important Note: For continuous distributions, the probability of getting exactly one specific value is 0. We can only find probabilities for ranges of values. That's why P(X < a) and P(X ≤ a) are the same for continuous distributions.

Using z-tables to Find Probabilities

The standard normal table (z-table) gives us P(Z ≤ z) — the probability that a standard normal variable is less than or equal to a particular z-score.

How to Read a z-table

Standard normal tables typically show:

  • Rows: The z-score to one decimal place (e.g., 1.2, 1.3)
  • Columns: The second decimal place (e.g., .00, .01, .02)
  • Body: The cumulative probability P(Z ≤ z)

To find P(Z ≤ 1.25): Look at row 1.2, column .05 → probability ≈ 0.8944

Common z-table Values (Memorize These!)

Finding P(X < a): Left-Tail Probabilities

This is the most straightforward case — z-tables directly give us left-tail probabilities.

Steps to Find P(X < a):

  1. Convert x to a z-score: z = (x - μ) / σ
  2. Look up the z-score in the z-table
  3. The table value is your answer!

Example 1: Left-Tail Probability

Scenario: SAT scores are normally distributed with μ = 1050 and σ = 100.

Question: What is the probability a randomly selected student scores less than 1200?

Solution:

Step 1: Calculate the z-score

  • z = (1200 - 1050) / 100 = 150 / 100 = 1.5

Step 2: Look up z = 1.5 in the table

  • P(Z ≤ 1.5) = 0.9332

Answer: P(X < 1200) = 0.9332, or about 93.32% of students score below 1200.

Finding P(X > a): Right-Tail Probabilities

For right-tail probabilities (greater than), we use the complement rule:

Complement Rule:

P(X > a) = 1 - P(X ≤ a)

Since the total probability is 1, the probability of being above a value equals
1 minus the probability of being at or below that value.

Steps to Find P(X > a):

  1. Convert x to a z-score: z = (x - μ) / σ
  2. Look up the z-score in the z-table to find P(Z ≤ z)
  3. Subtract from 1: P(Z > z) = 1 - P(Z ≤ z)

Example 2: Right-Tail Probability

Scenario: SAT scores: μ = 1050, σ = 100

Question: What percentage of students score above 1200?

Solution:

Step 1: Calculate z-score

  • z = (1200 - 1050) / 100 = 1.5

Step 2: Find P(Z ≤ 1.5) from table

  • P(Z ≤ 1.5) = 0.9332

Step 3: Use complement rule

  • P(X > 1200) = P(Z > 1.5) = 1 - 0.9332 = 0.0668

Answer: About 6.68% of students score above 1200.

Finding P(a < X < b): Between Two Values

To find the probability that X falls between two values, we use subtraction:

Probability Between Two Values:

P(a < X < b) = P(X < b) - P(X < a)

Find the area to the left of b, then subtract the area to the left of a

Steps to Find P(a < X < b):

  1. Convert both values to z-scores
  2. Look up both z-scores in the table
  3. Subtract: P(z₁ < Z < z₂) = P(Z ≤ z₂) - P(Z ≤ z₁)

Example 3: Probability Between Two Values

Scenario: SAT scores: μ = 1050, σ = 100

Question: What percentage of students score between 950 and 1200?

Solution:

Step 1: Calculate z-scores

  • z₁ = (950 - 1050) / 100 = -1.0
  • z₂ = (1200 - 1050) / 100 = 1.5

Step 2: Look up both z-scores

  • P(Z ≤ -1.0) = 0.1587
  • P(Z ≤ 1.5) = 0.9332

Step 3: Subtract

  • P(950 < X < 1200) = 0.9332 - 0.1587 = 0.7745

Answer: About 77.45% of students score between 950 and 1200.

Working Backwards: Finding Values from Percentiles

Sometimes we know the probability and need to find the corresponding value. This is called finding a percentile.

What is a Percentile?

The kth percentile is the value below which k% of the data falls.

Examples:

  • 50th percentile = median (50% below, 50% above)
  • 90th percentile = 90% of values are below this point
  • 25th percentile = first quartile (Q1)

Steps to Find a Percentile:

  1. Look up the probability in the body of the z-table
  2. Find the corresponding z-score from the row/column
  3. Convert back to original value: x = μ + z·σ

Example 4: Finding a Percentile

Scenario: SAT scores: μ = 1050, σ = 100

Question: What score represents the 90th percentile?

Solution:

Step 1: Find z-score for 90th percentile (probability = 0.90)

  • Look in z-table body for value closest to 0.9000
  • We find 0.8997 at z = 1.28
  • So the 90th percentile is approximately z = 1.28

Step 2: Convert to original scale

  • x = μ + z·σ = 1050 + (1.28)(100) = 1050 + 128 = 1178

Answer: A score of about 1178 is the 90th percentile. 90% of students score below 1178.

Example 5: Finding a Lower Percentile

Scenario: Test scores: μ = 75, σ = 8

Question: Below what score do the bottom 10% of students fall?

Solution:

Step 1: Find z-score for 10th percentile (probability = 0.10)

  • Look for 0.1000 in z-table body
  • Closest value is 0.1003 at z = -1.28
  • Note: Negative z because we're below the mean

Step 2: Convert to original scale

  • x = μ + z·σ = 75 + (-1.28)(8) = 75 - 10.24 = 64.76

Answer: The bottom 10% score below about 65.

Check Your Understanding

Try these questions to test what you've learned in this lesson.

Question 1: Heights of women are N(65, 2.5) inches. What is the probability a randomly selected woman is shorter than 67.5 inches? (Note: z = 1.0 gives P(Z ≤ 1) = 0.8413)

Answer: 0.8413 or 84.13%

Solution:

  • z = (67.5 - 65) / 2.5 = 2.5 / 2.5 = 1.0
  • P(Z ≤ 1.0) = 0.8413

Question 2: Using the same distribution, what percentage of women are taller than 67.5 inches?

Answer: 15.87%

Solution:

  • From Question 1: P(X < 67.5) = 0.8413
  • P(X > 67.5) = 1 - 0.8413 = 0.1587

Question 3: IQ scores are N(100, 15). Find P(IQ < 85). (Hint: z = -1 gives P(Z ≤ -1) = 0.1587)

Answer: 0.1587 or 15.87%

Solution:

  • z = (85 - 100) / 15 = -15 / 15 = -1.0
  • P(Z ≤ -1) = 0.1587

Question 4: Battery life is N(500, 50) hours. What's the probability a battery lasts between 450 and 600 hours? (z = -1: 0.1587, z = 2: 0.9772)

Answer: 0.8185 or 81.85%

Solution:

  • z₁ = (450 - 500) / 50 = -1, P(Z ≤ -1) = 0.1587
  • z₂ = (600 - 500) / 50 = 2, P(Z ≤ 2) = 0.9772
  • P(450 < X < 600) = 0.9772 - 0.1587 = 0.8185

Question 5: Test scores are N(72, 10). What score represents the 75th percentile? (z = 0.67 gives P(Z ≤ 0.67) ≈ 0.75)

Answer: 78.7 (or approximately 79)

Solution:

  • For 75th percentile, we need z where P(Z ≤ z) = 0.75
  • From table: z ≈ 0.67
  • x = μ + z·σ = 72 + (0.67)(10) = 72 + 6.7 = 78.7

Key Takeaways from Lesson 3

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