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Lesson 3: Right Triangle Definitions of Trig Functions

Estimated time: 25-30 minutes

Learning Objectives

By the end of this lesson, you will be able to:

SOH-CAH-TOA

For an acute angle θ in a right triangle, the six trig functions are ratios of the sides relative to that angle.

SOH: sin θ = Opposite / Hypotenuse

CAH: cos θ = Adjacent / Hypotenuse

TOA: tan θ = Opposite / Adjacent

Reciprocal Functions:

csc θ = Hypotenuse / Opposite = 1/sin θ

sec θ = Hypotenuse / Adjacent = 1/cos θ

cot θ = Adjacent / Opposite = 1/tan θ

Labeling the Triangle

In a right triangle with acute angle θ:

Important: the labels "opposite" and "adjacent" change depending on which acute angle you are considering.

Worked Examples

Example 1: Finding All Six Trig Values

A right triangle has legs 3 and 4 and hypotenuse 5. Find all six trig functions of the angle θ opposite the side of length 3.

Solution: Opposite = 3, Adjacent = 4, Hypotenuse = 5

sin θ = 3/5    cos θ = 4/5    tan θ = 3/4

csc θ = 5/3    sec θ = 5/4    cot θ = 4/3

Example 2: Using the Pythagorean Theorem First

In a right triangle, the side opposite θ is 7 and the hypotenuse is 25. Find cos θ.

Solution:

Step 1: Find adjacent: a² + 7² = 25², a² = 625 − 49 = 576, a = 24

Step 2: cos θ = adjacent/hypotenuse = 24/25

Example 3: Given One Trig Value, Find Another

If tan θ = 5/12 and θ is acute, find sin θ and cos θ.

Solution:

Step 1: Set up: Opposite = 5, Adjacent = 12. Find hypotenuse: h = √(25 + 144) = √169 = 13

Step 2: sin θ = 5/13, cos θ = 12/13

Connecting to the Unit Circle

The right triangle and unit circle definitions are consistent. When we place an acute angle in standard position and drop a perpendicular from the unit circle to the x-axis, we get a right triangle with hypotenuse 1. The opposite side equals sin θ and the adjacent side equals cos θ.

Cofunctions

In a right triangle, the two acute angles are complementary (sum to 90°). This creates the cofunction relationships:

sin θ = cos(90° − θ) and cos θ = sin(90° − θ)

tan θ = cot(90° − θ) and sec θ = csc(90° − θ)

Example 4: Cofunction

sin 40° = cos 50° (since 40 + 50 = 90).

tan 25° = cot 65° (since 25 + 65 = 90).

Check Your Understanding

1. In a right triangle with legs 8 and 15, find sin θ where θ is opposite the side of length 8.

Hypotenuse = √(64+225) = √289 = 17. sin θ = 8/17.

2. If cos θ = 3/7, find sin θ (assume θ acute).

sin²θ = 1 − 9/49 = 40/49. sin θ = √40/7 = 2√10/7.

3. Express cos 72° as a function of a complementary angle.

cos 72° = sin 18° (since 72 + 18 = 90).

Key Takeaways

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Lesson 4: Solving right triangles and real-world applications.

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